7m^2-7m+1=2m^2+4m-1

Solution for 7m^2-7m+1=2m^2+4m-1 equation:

7m^2-7m+1=2m^2+4m-1

We move all terms to the left:

7m^2-7m+1-(2m^2+4m-1)=0

We get rid of parentheses

7m^2-2m^2-7m-4m+1+1=0

We add all the numbers together, and all the variables

5m^2-11m+2=0

a = 5; b = -11; c = +2;
Δ = b2-4ac
Δ = -112-4·5·2
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-9}{2*5}=\frac{2}{10}
=1/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+9}{2*5}=\frac{20}{10}
=2
$